Examples.
Example 1.
Find the least common multiple (LCM) of numbers 12 and 16.
Solution.
12 = 2*2*3;
16 = 2*2*2*2.
We choose the number 16. From the factorization of the number 12 we add to its factors the factor 3, which the number 16 does not have: 2*2*2*2*3=48.
Therefore, LCM(12, 16) = 48.
If you choose the number 12, then from the factorization of the number 16 you need to add the factor 2 twice, since in the number 12 there are only two factors of 2, and in the number 16 there are four: 2*2*3*2*2=48.
Therefore, LCM(12, 16) = 48.
Answer: 48.
Example 2.
Find the least common multiple (LCM) of numbers 396 and 180.
Solution.
396 = 2*2*3*3*11;
180 = 2*2*3*3*5.
We choose the number 396. From the factorization of the number 180 we add to its factors the factor 5, which the number 396 does not have. That is, 2*2*3*3*11*5=1980.
Therefore, LCM(396, 180) = 1980.
Answer: 1980.
Example 3.
Find the least common multiple (LCM) of numbers 34, 51 and 68.
Solution.
34 = 2*17;
51 = 3*17;
68 = 2*2*17.
We choose the number 34. From the factorization of the number 51 we add to its factors the factor 3, which the number 34 does not have. We obtain the factorization 2*17*3. From the factorization of the number 68 we add to its factors the factor 2, since in the number 68 there are two factors of 2, and in our expansion there is one factor of 2. That is, 2*17*3*2=204.
Therefore, LCM(34, 51, 68) = 204.
Answer: 204.
Example 4.
Find the least common multiple (LCM) of numbers 10, 21 and 36.
Solution.
10 = 2*5;
21 = 3*7;
36 = 2*2*3*3.
We choose the number 10. From the factorization of the number 21 we add to its factors the factors 3 and 7, which the number 10 does not have. We obtain the factorization 2*5*3*7. From the factorization of the number 36 we add to its factors the factors 2 and 3, since in the number 36 there are two factors of 2 and two factors of 3, and in our factorization there is one factor of 2 and one factor of 3. That is, 2*5*3*7*2*3=1260.
Therefore, LCM(10, 21, 36) = 1260.
Answer: 1260.
Example 5.
Find the least common multiple (LCM) of numbers 12, 30, 60 and 75.
Solution.
12 = 2*2*3;
30 = 2*3*5;
60 = 2*2*3*5;
75 = 3*5*5.
We choose the number 12. From the factorization of the number 30 we add to its factors the factor 5, which the number 12 does not have. We obtain the factorization 2*2*3*5. From the factorization of the number 60 we don't add anything, since all its factors are present in our factorization. From the factorization of the number 75 we add to its factors the factor 5, since in the number 75 there are two factors of 5, and in our factorization there is one factor of 5. That is, 2*2*3*5*5=300.
Therefore, LCM(12, 30, 60, 75) = 300.
Answer: 300.