Lengths of chords, tangents, secants and angles between them

Lengths of chords, tangents and secants


1. The products of the chord segments are equal: AK * KB = CK * KD. Products of chord segments 2. A diameter perpendicular to a chord divides it in half: BD⊥EF => EA = AF. Diameter perpendicular to the chord 3. The midpoint perpendicular to the chord passes through the center of the circle: EA = AF, BD⊥EF => центр O∈BD.
Midpoint perpendicular to the chord 4. The segments of tangents coming from one point are equal: CF = CE. Equal tangent segments
5. Products of segments of secant segments coming from one point: BF*BD = BG*BE = BC2. Product of secant segments
6. The line passing through the intersection points of two circles divides their common tangent in half: AD = DB. General tangent

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Angles between chords, tangents and secants


1. The vertical angles between intersecting chords are equal to half the sum of the magnitudes of the arcs enclosed between their sides: ∠AKC = ∠BKD = ½(∪AC + ∪BD). Angles between chords
2. The angle between a tangent and a chord coming from one point on a circle is half of the magnitude of the arc between them: ∠BAE = ½(∪AB). Angle between tangent and chord
3. The angle between two tangents coming from the same point is equal to the half difference of the magnitudes of the arcs enclosed between its sides: ∠FCE = ½(∪FDE - ∪FBE). Angle between tangents
4. The angle between the tangent and the secant coming from the same point is equal to the half difference of the magnitudes of the arcs enclosed between its sides: ∠DBC = ½(∪CD - ∪CF).
    The angle between two secants originating from the same point is equal to the half-difference of the magnitudes of the arcs enclosed between its sides: ∠DBE = ½(∪DE - ∪FG). Angle between tangent and secant
5. If two equal angles rest on the same segment, a circle can be drawn through the vertices of the angles and the ends of the segment: A circle through the vertices of equal angles
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