Problem description:
There are 33 students in the class, among them are Mike and Ken.
The class is divided into three equal groups.
Find the probability that Mike and Ken will be in the same group.
Problem solution:
We will consider available places in groups, not people.
There are a total of thirty-three available seats, with 11 seats in each group.
Let Mike take one seat. So there are 32 seats left, and for Ken to get into the same group with Mike, there are 10 seats.
Therefore, the probability Ken will go into the same group with Mike is:
Answer: probability of the event Mike and Ken will be in the same group is 0.3125
Next probability problem solution:
Calculate probability of two girls sitting side by side
