Three dice are thrown. Find the probability that out of 3 dice, six dots(pips) will be thrown on at least one die.

The probability P that of not getting six on any of the three dice is:

P = (1 - ^{3} =

1/6

)125/216

Therefore, the probability of getting six on at least one of the dice is equal to:

1 -

125/216

= 91/216

91/216

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